Complex Number Division Formula
Let z₁ = a + bi, z₂ = c + di eq 0, then (z₁)/(z₂) = ((a + bi)(c - di))/((c + di)(c - di)) = (ac + bd)/(c²⁺d²) + (bc - ad)/(c²⁺d²)i. Applicable conditions: Divi…
Syllabus path: Geometry and Algebra › Vectors and Complex Numbers › Arithmetic Operations on Complex Numbers
CSCA Exam Prep
This formula is aligned to the CSCA undergraduate admissions exam syllabus. Continue with the linked tutorial and topic practice.
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CSCA Mathematics Formula Reference
Formula and explanation
Let z₁ = a + bi, z₂ = c + di eq 0, then (z₁)/(z₂) = ((a + bi)(c - di))/((c + di)(c - di)) = (ac + bd)/(c²⁺d²) + (bc - ad)/(c²⁺d²)i. Applicable conditions: Divisor z₂ eq 0. Explanation: Multiply numerator and denominator by the conjugate of the denominator to make the denominator real.
Related tutorial and examples
Arithmetic Operations on Complex Numbers
Arithmetic Operations on Complex Numbers Operations on complex numbers combine algebra and geometry. In the CSCA exam, Division (rationalizing the denominator) and Multiplication (using i² = - 1 ) are high - frequency calculation topics. Additionally, understanding the geometric …
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