Back to Physics syllabus

Newton's Laws of Motion and Their Applications

CSCA Newton's Laws of Motion and Their Applications study guide organized around the publicly available CSCA syllabus. Practice Physics questions on aicsca.com.

Before planning this topic, check the CSCA Exam Guide 2026 for exam dates, registration, fees, and subject requirements.

Syllabus Alignment

This study guide is organized around the publicly available CSCA syllabus for international undergraduate applicants.

Who It Is For

International students preparing for CSCA Math, Physics, Chemistry, or Chinese exams.

Related Practice

CSCA Practice · Go to questions

Past papers and worked video solutions · Timed mock exams · All subject video lessons

Practice by Topic

Jump from this tutorial to filtered practice questions for the same knowledge point.

Related formulas, concepts, and glossary terms

Physics Formula & Concept Reference

Physics Exam Glossary

Tutorial Content

Newton's Laws of Motion and Their Applications

1. Overview

Newton's laws establish the causal link between "Force" and "Motion".

* **1st Law (Inertia)**: Force is the cause of **changing** motion, not maintaining it.

* **2nd Law (Dynamics)**: Quantifies the relationship ($F=ma$).

* **3rd Law (Interaction)**: Describes the nature of forces between objects.

2. Key Concepts & Exam Focus

#### A. Newton's First Law

* **Content**: An object remains at rest or in uniform motion unless acted upon by a net external force.

* **Focus**:

* **Inertia**: Depends ONLY on **Mass**, not velocity.

* **Equilibrium**: $a=0 \iff F_{\text{net}} = 0$.

#### B. Newton's Second Law

The core for calculation problems.

* **Formula**: $$\vec{F}_{\text{net}} = \sum \vec{F} = m\vec{a}$$

* **Key Properties**:

1. **Vector Nature**: Calculate x and y components independently.

2. **Instantaneity**: If Force changes, Acceleration changes instantly.

3. **Same-Object**: $F, m, a$ must refer to the same system.

#### C. Newton's Third Law

* **Formula**: $\vec{F}_{A \to B} = -\vec{F}_{B \to A}$

* **Trap Alert**: **Action-Reaction** vs. **Balanced Forces**.

* Action/Reaction: Act on **two different** objects (Cannot cancel out).

* Balanced Forces: Act on the **same** object (Can cancel out).

3. Systematic Approach: Free Body Diagram (FBD)

The "5-Step Method" for dynamics:

1. **Object**: Identify the system.

2. **Draw (FBD)**: Draw all forces (Gravity, Normal, Friction, Applied). **Draw forces received, not exerted.**

3. **Axes**: Establish a coordinate system.

* **Tip**: Align the x-axis with the direction of acceleration.

4. **Resolve**: Decompose forces not on the axes.

5. **Equations**:

* x-axis: $\sum F_x = ma$

* y-axis: $\sum F_y = 0$ (usually balanced vertically)

1

4. Classic Models

#### Model 1: Block on Horizontal Surface

When friction is involved, first find Normal Force $N$.

* y-axis: $N = mg + F_y$

* x-axis: $F_x - \mu N = ma$

#### Model 2: Inclined Plane

A must-know for CSCA. **Focus on decomposing Gravity ($mg$)**.

2

* **Axes**: x-axis along the slope, y-axis perpendicular to the slope.

* **Decomposition of Gravity**:

* Down-slope component: $F_{g,x} = mg \sin\theta$

* Perpendicular component: $F_{g,y} = mg \cos\theta$

* **Equations**:

* y-axis: $N - mg \cos\theta = 0 \Rightarrow N = mg \cos\theta$

* x-axis (if frictionless): $mg \sin\theta = ma \Rightarrow a = g \sin\theta$

5. Typical Example

**Example: Friction on an Incline**

**Problem**: A block of mass $m=2\text{kg}$ slides down a rough incline (angle $\theta=30^\circ$) at constant velocity. Find the coefficient of kinetic friction $\mu$.

**Solution**:

1. **FBD**: Gravity $mg$, Normal force $N$, Friction $f$ (up the slope).

2. **State**: Constant velocity $\Rightarrow a=0 \Rightarrow F_{\text{net}}=0$.

3. **Equations**:

* Perpendicular: $N = mg \cos30^\circ$

* Parallel: $mg \sin30^\circ - f = 0 \Rightarrow f = mg \sin30^\circ$

4. **Solve**:

$f = \mu N \Rightarrow \mu (mg \cos30^\circ) = mg \sin30^\circ$

$\mu = \tan30^\circ = \frac{\sqrt{3}}{3} \approx 0.577$

**Conclusion**: The condition for sliding down at constant velocity is $\mu = \tan\theta$, independent of mass.