Work, Energy, and Conservation of Mechanical Energy
CSCA Work, Energy, and Conservation of Mechanical Energy study guide organized around the publicly available CSCA syllabus. Practice Physics questions on aicsca.com.
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Related formulas, concepts, and glossary terms
Physics Formula & Concept Reference
- Gravitational Potential Energy
- Gravitational Potential Energy Formula
- Formula for Work Done by a Constant Force
- Elastic Potential Energy Formula (Spring)
- Law of Conservation of Mechanical Energy
- Power (Average Power)
- Elastic Potential Energy (Spring)
- Work - Energy Theorem
Physics Exam Glossary
Tutorial Content
Work, Energy, and Conservation of Mechanical Energy
1. Overview
Work and Energy are the core languages for describing "interactions" and "state changes". Derived from Newton's laws, the **Work-Energy Theorem** and **Conservation of Mechanical Energy** provide simpler methods than Newton's Second Law for solving non-uniform motion problems (like curved motion or variable forces).
* **Work**: The measure of energy transfer (Process Quantity).
* **Energy**: The capacity to do work (State Quantity).
2. Work
#### A. Definition & Formula
Work is the accumulation of force over space.
* **Formula**: $$W = F s \cos\theta$$
* $F$: Magnitude of Force.
* $s$: Magnitude of **Displacement** (relative to ground).
* $\theta$: Angle between Force and Displacement vectors.

#### B. Positive vs. Negative Work
* **$0^\circ \le \theta < 90^\circ$**: **Positive Work** (Driving force), promotes motion.
* **$\theta = 90^\circ$**: **No Work** (e.g., Lorentz force, Centripetal force).
* **$90^\circ < \theta \le 180^\circ$**: **Negative Work** (Resisting force), hinders motion.
3. Work-Energy Theorem
The preferred tool for relating force and displacement for a **single object**, especially when **time is not involved**.
* **Statement**: The net work done on an object equals the change in its kinetic energy.
* **Formula**:
$$W_{\text{net}} = W_1 + W_2 + ... = \Delta E_k = \frac{1}{2}mv_2^2 - \frac{1}{2}mv_1^2$$
**CSCA Exam Tip**:
To calculate $W_{\text{net}}$, you have two options:
1. Find Net Force $F_{\text{net}}$ first, then calculate Work (for constant forces).
2. Calculate work for each force individually, then sum them up algebraically (for variable forces or multi-stage motion).
4. Conservation of Mechanical Energy
#### A. Potential Energy (PE)
* **Gravitational PE**: $E_p = mgh$. Note that $h$ is height relative to a **Reference Plane** (usually the lowest point).
* **Work-PE Relation**: Gravity does positive work $\to$ PE decreases. $$W_G = -\Delta E_p = mgh_1 - mgh_2$$
#### B. The Law
* **Condition**: **Only Gravity or Elastic Force does work**.
* *Note: Other forces (like Normal force) can exist, but if they do zero work, energy is still conserved.*
* **Formula**:
1. **State Equation**: $$E_{k1} + E_{p1} = E_{k2} + E_{p2}$$
2. **Transformation Equation**: $$\Delta E_k = -\Delta E_p$$ (Gain in KE = Loss in PE)
5. Strategy: Work-Energy Theorem vs. Conservation?
| Scenario | Preferred Method | Reason |
| :--- | :--- | :--- |
| Friction or Air Resistance does work | **Work-Energy Theorem** | Mechanical energy is not conserved. This theorem applies to ALL processes. |
| Only Gravity/Spring force does work (Smooth slopes, pendulum, projectiles) | **Conservation Law** | Simpler. No need to calculate work; just equate states. |
| Finding work done by a variable force | **Work-Energy Theorem** | Use $\Delta E_k$ to solve for $W$ indirectly. |
6. Typical Examples
**Example 1: Work-Energy Theorem (with Friction)**
**Problem**: A $2\text{kg}$ block moves $5\text{m}$ under a pull $F=10\text{N}$ and friction $f=2\text{N}$. Find final speed ($v_0=0$).
**Solution**:
Net Work: $W_{\text{net}} = W_F + W_f = Fs - fs = 10\times5 - 2\times5 = 40\text{J}$.
Theorem: $40 = \frac{1}{2}mv^2 - 0 \Rightarrow 40 = v^2 \Rightarrow v = \sqrt{40} \approx 6.32\text{m/s}$.
**Example 2: Conservation (Pendulum)**
**Problem**: A ball on a string of length $L$ is released from rest at an angle of $60^\circ$. Find speed at the lowest point.
**Solution**:
1. **Check**: Only Gravity does work (Tension is perpendicular) $\to$ Conserved.
2. **Ref**: Lowest point is $h=0$.
3. **Height**: Initial height $h = L - L\cos60^\circ = \frac{1}{2}L$.
4. **Calc**:
$$mgh = \frac{1}{2}mv^2$$
$$g(\frac{1}{2}L) = \frac{1}{2}v^2 \Rightarrow v = \sqrt{gL}$$